Уравнения, системы уравнений и неравенства

x\cdot x=x+x
x₁ = ; x₂ = 

2u^2+7u=-6
u₁ = ; u₂ = 

x\left(2x+1\right)=x\left(3+4x\right)
x₁ = ; x₂ = 

4\left(x+6\right)\left(x-3\right)=0
x₁ = ; x₂ = 

\frac{5}{x}=x+4
x₁ = ; x₂ = 

\frac{x}{x+2}+\frac{x+2}{x}=\frac{10}{3}
x₁ = ; x₂ = 

\frac{2x-1}{2x+1}=\frac{2x+1}{2x-1}+\frac{8}{1-4x^2}
x = 

2-\frac{x-5}{x-1}=\frac{x+3}{x-2}
x = 

Ответ: $\left\{\begin{array}{l}x=\mathrm{<semantics\; class="mathml-form-input"><annotation-xml\; encoding="application/xhtml+xml"><span\; class="gap\; fourth"\; data-key="8fb149de-4093-489c-87d5-33699e8fab95"\; contenteditable="true"\; xmlns="http://www.w3.org/1999/xhtml"\; data-empty-is-error="true"></span></annotation-xml></semantics>}\\ y=\mathrm{<semantics\; class="mathml-form-input"><annotation-xml\; encoding="application/xhtml+xml"><span\; class="gap\; fourth"\; data-key="c413a259-cc85-4b4f-988c-7bcd1aa3ead2"\; contenteditable="true"\; xmlns="http://www.w3.org/1999/xhtml"\; data-empty-is-error="true"></span></annotation-xml></semantics>}\end{array}\right.$

Ответ: $\left\{\begin{array}{l}x=\mathrm{<semantics\; class="mathml-form-input"><annotation-xml\; encoding="application/xhtml+xml"><span\; class="gap\; fourth"\; data-key="0a9ed993-2a84-4c6f-85df-253079a6c7ad"\; contenteditable="true"\; xmlns="http://www.w3.org/1999/xhtml"\; data-empty-is-error="true"></span></annotation-xml></semantics>}\\ y=\mathrm{<semantics\; class="mathml-form-input"><annotation-xml\; encoding="application/xhtml+xml"><span\; class="gap\; fourth"\; data-key="23b17f41-03d0-46db-b8ac-d6d9c9876fcd"\; contenteditable="true"\; xmlns="http://www.w3.org/1999/xhtml"\; data-empty-is-error="true"></span></annotation-xml></semantics>}\end{array}\right.$

Ответ: $\left\{\begin{array}{l}x=\mathrm{<semantics\; class="mathml-form-input"><annotation-xml\; encoding="application/xhtml+xml"><span\; class="gap\; fourth"\; data-key="8fc4a5a6-c0a3-407e-b824-1687e2afc660"\; contenteditable="true"\; xmlns="http://www.w3.org/1999/xhtml"\; data-empty-is-error="true"></span></annotation-xml></semantics>}\\ y=\mathrm{<semantics\; class="mathml-form-input"><annotation-xml\; encoding="application/xhtml+xml"><span\; class="gap\; fourth"\; data-key="58ada787-a34b-4914-8dca-3f0f348afaec"\; contenteditable="true"\; xmlns="http://www.w3.org/1999/xhtml"\; data-empty-is-error="true"></span></annotation-xml></semantics>}\end{array}\right.$

Ответ: $\left(\mathrm{<semantics\; class="mathml-form-input"><annotation-xml\; encoding="application/xhtml+xml"><span\; class="gap\; fourth"\; data-key="87fc9ef8-221a-49dc-a013-0a89d4df2393"\; contenteditable="true"\; xmlns="http://www.w3.org/1999/xhtml"\; data-empty-is-error="true"></span></annotation-xml></semantics>}; \mathrm{<semantics\; class="mathml-form-input"><annotation-xml\; encoding="application/xhtml+xml"><span\; class="gap\; fourth"\; data-key="c2d362d7-eabe-48a9-b9dd-8647023df2c2"\; contenteditable="true"\; xmlns="http://www.w3.org/1999/xhtml"\; data-empty-is-error="true"></span></annotation-xml></semantics>}\right)$ и $\left(\mathrm{<semantics\; class="mathml-form-input"><annotation-xml\; encoding="application/xhtml+xml"><span\; class="gap\; fourth"\; data-key="abc7213a-9d05-471a-942a-22be4248209f"\; contenteditable="true"\; xmlns="http://www.w3.org/1999/xhtml"\; data-empty-is-error="true"></span></annotation-xml></semantics>}; \mathrm{<semantics\; class="mathml-form-input"><annotation-xml\; encoding="application/xhtml+xml"><span\; class="gap\; fourth"\; data-key="0d8f4217-8d59-4a09-b602-68720f489b01"\; contenteditable="true"\; xmlns="http://www.w3.org/1999/xhtml"\; data-empty-is-error="true"></span></annotation-xml></semantics>}\right)$

Ответ: $\left(\mathrm{<semantics\; class="mathml-form-input"><annotation-xml\; encoding="application/xhtml+xml"><span\; class="gap\; fourth"\; data-key="0ff30888-9c04-489b-84b4-ec9b7154fea8"\; contenteditable="true"\; xmlns="http://www.w3.org/1999/xhtml"\; data-empty-is-error="true"></span></annotation-xml></semantics>}; \mathrm{<semantics\; class="mathml-form-input"><annotation-xml\; encoding="application/xhtml+xml"><span\; class="gap\; fourth"\; data-key="a6c5aa64-77de-4b18-970c-a57b2c204aa8"\; contenteditable="true"\; xmlns="http://www.w3.org/1999/xhtml"\; data-empty-is-error="true"></span></annotation-xml></semantics>}\right)$

Ответ: $\left(\mathrm{<semantics\; class="mathml-form-input"><annotation-xml\; encoding="application/xhtml+xml"><span\; class="gap\; fourth"\; data-key="620879ca-f6f8-4b81-8502-38784b91fd6a"\; contenteditable="true"\; xmlns="http://www.w3.org/1999/xhtml"\; data-empty-is-error="true"></span></annotation-xml></semantics>}; \mathrm{<semantics\; class="mathml-form-input"><annotation-xml\; encoding="application/xhtml+xml"><span\; class="gap\; fourth"\; data-key="9a33b751-df1c-4b4a-a9bb-22880c759503"\; contenteditable="true"\; xmlns="http://www.w3.org/1999/xhtml"\; data-empty-is-error="true"></span></annotation-xml></semantics>}\right)$

2\left(2x-1\right)<5\left(x-0,3\right)
x ∈ 

\frac{x-1}{3}-x>\frac{x+1}{2}
x ∈ 

$\left\{\begin{array}{l}2x+4\left(x-7\right)<2\\ \frac{2x - 8}{3}-\frac{3x}{2}<4\end{array}\right.$
x ∈ 

$\left\{\begin{array}{l}2x-4\ge 10x+12\\ x\left(x-4\right)\le -4\end{array}\right.$
x ∈ 

\left(5x-1\right)^2\ge36
x ∈ 

4y^2\le100
y ∈ 

x^2-12x+36\le0
x ∈ 

\left(t-3\right)\left(t+4\right)\le0
t ∈ 

\left(x-2\right)^2+3\ge0
x ∈ 

-x^2+\frac{2x}{3}>\frac{1}{9}
x ∈