Avaldiste teisendamine

2(a + 1)(a² + 1) – (a – 1)(a² + 1) – (a + 3)(a² – 1) = 

(n – 1)(n – 2) – (n + 3)(n – 2) + (n + 3)(n + 2) = 

(5 – 3x)(2x – 1) – (x + 1)(x – 4) + x(6 – x) = 

(m + 1)² + 3(m – 1)² – 5(m + 1)(m – 1) = 

–(3 + x)² + 5(1 – x)² – 3(1 – x)(1 + x) = 

4(m + 3n)² + 3(4m – n)² – 2(m + n)(m – n) = 

$\left(\frac{x}{2}+\frac{y}{3}\right):\left(\frac{x}{3}+\frac{y}{2}\right)$ = 

$\left(\frac{12a{b}^2 + 10b^2 - 9a}{6a{b}^3}-\frac{4a - 5a^2}{4a^{2}b}\right):\frac{5}{6a{b}^3}$ = 

$\left(2y+3x-\frac{2x^2 - y^2}{x}\right):{\left(x+y\right)}^2$ = 

$\left(\frac{y^2 - 2x^2}{2x{y}^2}+\frac{y}{x^2}\right)·\frac{4xy}{5}$ = 

$\frac{4}{x + 2}-\frac{3}{x - 2}-\frac{x + 2}{x^2 - 4}$ = 

$\frac{1}{a + 2}-\frac{1}{2 - a}-\frac{4}{a^2 - 4}$ = 

$\frac{m - n}{2m + 2n}+\frac{m^2 + n^2}{n^2 - m^2}$ = 

$\frac{x^2 + y^2}{x^2 - y^2}-\frac{x + y}{2x - 2y}$ = 

$\frac{7a - 1}{2a^2 + 6a}+\frac{5 - 3a}{a^2 - 9}$ = 

$\frac{a - b}{5a + 5b}+\frac{a^2 + b^2}{b^2 - a^2}$ = 

$\frac{a^2 - 4b^2}{a^2 - ab}·\frac{a - b}{a^2 + 2ab}$ = 

$\frac{3m^2 - 3n^2}{m^2 + mp}:\left(-\frac{6n - 6m}{m + p}\right)$ = 

$\frac{4}{3m - 3n}+\frac{3m - n}{2m^2 - 4mn + 2n^2}$ = 

$\frac{1}{2x + 2}-\frac{x - 1}{3x^2 + 6x + 3}$ = 

$\left(\frac{1}{a^2 - b^2}+\frac{1}{a^2 + 2ab + b^2}\right)·\frac{2ab - a^2 - b^2}{a^2 - b^2}$ = 

$\frac{a}{1 - a}:\left(a+1-\frac{1 - 2a^2}{1 - a}\right)$ = 

$\frac{1}{1 - a^2}·\frac{a^2 - 1}{a + 2}-\frac{2}{a^2 + 2a}$ = 

$\left(\frac{n^2 - an}{n^2 - a^2}+\frac{a}{a + n}\right):\frac{a + n}{2}$ = 

$\left(\frac{m}{m - n}-\frac{mn + n^2}{n^2 - m^2}\right)-\frac{m - n}{{\left(m + n\right)}^2}$ = 

$\frac{a}{a^2 - 2a + 1}-\frac{a}{1 - a^2}-\frac{2}{a + 1}$ = 

$\frac{x^2 - xy + y^2}{xy\left(y + x\right)}:\left(\frac{y^2}{x^3 - x{y}^2}+\frac{1}{x + y}\right)$ = 

$\frac{1}{3\left(a^2 + 3a + 2\right)}+\frac{1}{3 - 3a^2}-\frac{1}{a^2 + a - 2}$ = 

$\frac{2\left(a + 2\right)}{a^2 + 4a + 3}:\left(\frac{1}{a^2 + 5a + 6}+\frac{1}{a^2 + 3a + 2}\right)$ =